Capacitors

We took a quiz in the beginning of class and this was the correct way to solve the problem. It was a system of equations for chosen loops throughout a circuit. We solved for each unknown then found the total power at the end.

For the experiment above we calculated the capacity through a set number of pages between two aluminum sheets. We graphed the results to show that thickness between the aluminum sheets was inversely proportional to the capacity of them.

In the picture above we calculated the surface area of an a square paper that had the capacity of 1 Farad, a k constant of 3.5, and a the distance from another square paper of 1 millimeter. The surface area needed to get the capacity of 1 Farad was huge, 3.55 miles.

In the three pictures above we found the capacity of 2 capacitors in series, then in parallel, and in the last picture we found the capacity of 1 capacitor.

In the picture above we have are illustration of the experiment conducted in the 3 above pictures, where we found the capacities of 2 capacitors in series and in parallel. Then in the bottom right we calculated the total capacity of the shown alignment of capacitors and batteries. Afterward we calculated the energy of the system, voltage of the unknown battery, and charges of the system.